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Andreyy89
3 years ago
13

The population of a city in 2005 was 15,000. By 2015, the city's population had grown to 45,000 people. Assuming that the popula

tion of the city has grown linearly since 2005 and continued to grow at the same rate, what will be the population in 2025?
Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0

Answer:

The population of the city in the year 2025 will be 85,000.

Step-by-step explanation:

The population of the city in year 2005 = 15,000

The population of the city in the year 2015  = 45,000

⇒ The change in population in 10 years

= Population in year 2015 - Population in the year 2005

= 45,000  - 15, 000

= 30,000

⇒ The change in population in 10 years  = 30,000

Now, the population in the year 2015 = 45, 000

Let us assume the number of population in the year 2025 = m

Here, according to the question:

Since, the CHANGE OF RATE is a linear growth since 2005.

⇒ The change in population in each 10 years  = 30,000

⇒ The change in population in next 10 years

  = Population in year 2025 - Population in the year 2015

or, 30, 000 = m - 45, 000

⇒ m = 30,000 + 45,000 = 85,000

or, m = 85,000

Hence, the population of the city in the year 2025 will be 85,000.

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Step-by-step explanation:

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Cost = \$28

Step-by-step explanation:

Given

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The second statement, we have:

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Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

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4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

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Multiply through by 4

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Open bracket

196 - 35h + 12h = 104

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Collect Like Terms

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Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

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