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vitfil [10]
3 years ago
8

Solve x3 = 1/8 can someone tell me what the answer for this problem is?

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0
Divide 1/8 by 3. If you have a calculator you can type in “(1/8)/3”.
madreJ [45]3 years ago
7 0

Answer:

x=1/24 or 24*1=24

Step-by-step explanation:

x*3=1/8

First you divide by 3 from both sides of an equation form.

\frac{x*3}{3}=1/8/3

Then simplify.

8*3=24

x=1/24 or 1/24=x

Final answer: x=1/24

Hope this helps!

And thank you for posting your question at here on brainly.

Have a great day!

-Charlie

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Timber beams are widely used in home construction. When the load​ (measured in​ pounds) per unit length has a constant value ove
Delicious77 [7]

Answer:

a) 0.4

b) 0.133

c) L \geq 99  

Step-by-step explanation:

We are given the following information in the question:

The load is said to be uniformly distributed over that part of the beam  between 90 and 105 pounds per linear foot.

a = 90 and b = 105

Thus, the probability distribution function is given by

f(x) = \displaystyle\frac{1}{b-a} = \frac{1}{105-90} = \frac{1}{15},\\\\90 \leq x \leq 105

a) P( beam load exceeds 99 pounds per linear​ foot)

P( x > 99)

=\displaystyle\int_{99}^{105} f(x) dx\\\\=\displaystyle\int_{99}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{99}^{105} = \frac{1}{15}(105-99) = 0.4

b) P( beam load less than 92 pounds per linear​ foot)

P( x < 92)

=\displaystyle\int_{90}^{92} f(x) dx\\\\=\displaystyle\int_{90}^{92} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{90}^{92} = \frac{1}{15}(92-90) = 0.133

c) We have to find L such that

\displaystyle\int_{L}^{105} f(x) dx\\\\=\displaystyle\int_{L}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{L}^{105} = \frac{1}{15}(105-L) = 0.4\\\\\Rightarrow L = 99

The beam load should be greater than or equal to 99 such that the probability that the beam load exceeds L is 0.4.

4 0
4 years ago
the equation of a line is y=-1/2x-2. what is the equation of the line that is perpendicular to the first line and passes through
Alexxandr [17]
Perpendicular means that the slopes are negartive inverses, aka
slope1 times slope2=-1

y=mx+b
slope=m

y=-1/2x-2
slope=-1/2

we need to find negative inverse
-1/2 times what=-1
answer is 2

y=2x+b
input the point (2,-2) to find b
(x,y)
(2,-2)
-2=2(2)+b
-2=4+b
minus 4 from both sides
-6=b
y=2x-6

the equtaion is y=2x-6
8 0
3 years ago
What is the answer to this equation?:<br> 4(3x) + 7 - 5x - 5 + 3y - y
Anika [276]

Answer:  7x + 2y + 2

Step-by-step explanation:

4(3x) + 7 - 5x - 5 + 3y - y

= 12x + 7 - 5x - 5 + 3y - y

= 7x + 2y + 2

4 0
3 years ago
If 10000 is invested at an interest rate of 10 per year ,compound semiannually,find the value of the investment after the given
slega [8]

Answer:

Part a) \$17,958.56  

Part b) \$32,251.00  

Part c) \$57,918.16

Step-by-step explanation:

<u><em>The complete question is</em></u>

If $10,000 is invested at an interest rate of 10% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

Part a) 6 years

we have  

t=6\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*6}  

A=10,000(1.05)^{12}  

A=\$17,958.56  

Part b) 12 years

we have  

t=12\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*12}  

A=10,000(1.05)^{24}  

A=\$32,251.00  

Part c) 18 years

we have  

t=18\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2  

substitute in the formula above  

A=10,000(1+\frac{0.10}{2})^{2*18}  

A=10,000(1.05)^{36}  

A=\$57,918.16

7 0
4 years ago
For the equation y=3x^2+12x-4, what is the minimum value?
Neko [114]

Answer:

(-2, -16)

Step-by-step explanation:

the minimum is at the vertex which can be found using -b/2a for the x-value of the vertex.

y = 3x^2 + 12x - 4

  = ax^2 + bx - c

b = 12, a = 3

-12/(2(3))

-12/6

x = -2

y = 3(-2)^2 + 12(-2) - 4

y = -16

(-2, -16)

4 0
3 years ago
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