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d1i1m1o1n [39]
3 years ago
6

Well happy New Year everyone. I've been thinking about the upcoming year "2021" and found something interesting. Reduced to its

prime factors it becomes 43*47. Yes, it resolves into 2 CONSECUTIVE 2 digit prime numbers, which does NOT happen that often. The last time this occurred was in 1927 (41 * 47). However these are NOT consecutive prime numbers. (There's another prime number between 41 and 47). If we go back to 1763 (41 * 43), it resolves into two 2-digit CONSECUTIVE primes AND they are TWIN primes (prime numbers with a difference of 2).
And now, here's the question: Can anyone find some interesting factorizations of upcoming years? For example, the year 2033 = 19*107 and the year 2041 = 13*157. In each case the factors are less than 10. Obviously, this is not THE most vital question, so don't spend too much time on it. (Although I've been told that a solution will finally bring about World Peace!!! ) LOL
Mathematics
1 answer:
Anarel [89]3 years ago
5 0

Answer:

As 2021 and 1927 does not have any product of primes

HCF and LCM of 2020 and 1926 is shown below

Step-by-step explanation:

2020 = 2^2 × 5 × 101

1926 = 2 x 3^2 x 107

2  is the HCF

2 x 2 x 3 x 3 x 5 x 101 x 107  = 1945260

1945260 is the LCM

2022 and 1928 both have product of primes and their HCF and LCM is

1949208 is the LCF and 2 is the HCF

1949208 - 1945260 = 3948

3948/2 = 1974

2022-1928 = 94

2020 - 1926 = 94

1974/94 = 21

and brings us back to our year again.

Happy New Year to you.

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Free_Kalibri [48]

Answer:

I'm sorry but I don't know English so I can't help you

Step-by-step explanation:

how do i tell you i don't know english so i can't help you friendy and well, I don't know why it won't let me upload my answer xd

6 0
3 years ago
Can anyone help with these maths questions about transformations please?
salantis [7]
A. Reflection over y = 2

B. Reflection over y axis, reflection over y = 1

C. I'm guessing you just have to draw this one, just put the center on (2,0) and enlarge it by the scale factor
8 0
3 years ago
Answer the question for a normal random variable x with mean μ and standard deviation σ specified below. (Round your answer to o
vladimir2022 [97]

Answer:

x = 63.6

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X and also the area to its left. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to its right.

In this problem, we have that:

\mu = 38, \sigma = 11

Find a value of x that has area 0.01 to its right

This is x when Z has a pvalue of 1-0.01 = 0.99. So it is X when Z = 2.3267.

Z = \frac{X - \mu}{\sigma}

2.3267 = \frac{X - 38}{11}

X - 38 = 11*2.3267

X = 63.6

So x = 63.6

6 0
3 years ago
Name a pair of Alternate Exterior Angles
pogonyaev

Answer:

M, Z

O, X

P, W

N, Y

Step-by-step explanation:

They are all Alternate Exterior Angles.

<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!</em>

4 0
2 years ago
Read 2 more answers
HOW DO I FIND QR<br><br> PLEASE HELP
Paul [167]

Solution: For finding QR we need to apply Pythagoras Theorem

What is Pythagoras Theorem ?

ans : Pythagoras Theorem is the sum of square of two sides which is equal to the third side or the hypotenuse. This formula is valid oy incase of Right-Angled Traingle because one of three angles here is 90°

According to this law let's apply it in the diagram shown here.

  • (Hypotenuse)² = (Adjacent)² + (Opposite)²

  • (PR)² = (QR)² + (PQ)²

  • (5x - 2)² = (QR)² + (3x - 1)²

  • (QR)² = (5x - 2)² - (3x - 1)²

After factorising both of them we get

  • (QR)² = 25x² - 20x + 4 - (9x² - 6x + 1)

  • (QR)² = 25x² - 20x + 4 - 9x² + 6x - 1

  • (QR)² = 16x² - 14x + 3

  • QR = √(16x² - 14x + 3)

So, QR is √(16x² - 14x + 3)

8 0
3 years ago
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