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Hoochie [10]
3 years ago
13

Saguaro cacti are large cacti indigenous to thesouthwestern United States and Mexico. Assume that thenumber of saguaro cacti in

a region follows a Poisson distributionwith a mean of 280 per square kilometer. Determinethe following:(a) Mean number of cacti per 10,000 square meters.(b) Probability of no cacti in 10,000 square meters.(c) Area of a region such that the probability of at least twocacti in the region is 0.9.
Mathematics
1 answer:
pickupchik [31]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that Saguaro cacti are large cacti indigenous to thesouthwestern United States and Mexico. Assume that thenumber of saguaro cacti in a region follows a Poisson distribution with a mean of 280 per square kilometer.

a) Mean number of cacti per 10,000 square meters=280*10000 = 2800000

b) P(no cacti in 10000) sq m = P(X=0) for Poisson with parameter 2800000

= 0

(almost uncertain event)

c) Area of a region such that the probability of at least twocacti in the region is 0.9.

P(X\geq 2) =0.9\\

We get this is possible if mean = 8.4 for Poisson

i.e. region should have area as

\frac{8.4}{280} \\=0.03

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The distribution of heights of adult males has a mean of 69 inches and a standard deviation of 4 inches. A random sample of 36 a
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Answer:

P(\bar X >70)= P(Z>\frac{70-69}{\frac{4}{\sqrt{36}}})= P(Z>1.5)

And for this case we can use the complement rule and the normal standard distribution of excel and we got:

P(Z>1.5)=1-P(Z,1.5) = 1-0.933=0.0668

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(69,4)  

Where \mu=69 and \sigma=4

And we select a sample size of n =70

From the central limit theorem  (n>30)we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >70)

And we can use the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

P(\bar X >70)= P(Z>\frac{70-69}{\frac{4}{\sqrt{36}}})= P(Z>1.5)

And for this case we can use the complement rule and the normal standard distribution of excel and we got:

P(Z>1.5)=1-P(Z,1.5) = 1-0.933=0.0668

6 0
4 years ago
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