Answer:
The distance of the overpass above the ground is approximately 26.795 ft
Step-by-step explanation:
The parameters given are;
The distance from the overpass the engineer stands before determining the angle of elevation of the overpass from his standing point = 100 ft
The angle of elevation of the overpass as determined by the engineer from 100 ft = 15°
By trigonometric ratios, we have;

The opposite side to the 15° angle of elevation in the above case is the distance of the overpass above the ground
The opposite side to the 15° is the distance of the engineer from the base of the overpass
Therefore;
Tan(15°) the height of the overpass=
length

The distance of the overpass above the ground = 100 × tan (15°) ≈ 26.795 ft.
Answer:
Step-by-step explanation:
So you should know. Can you give us a better picture?
Answer:
1 g = .001 kg
4 kg = 4000 g
Step-by-step explanation:
1 kg = 1000 g
0.1 kg = 100 g
.01 kg = 10 g
.001 kg = 1 g
4 kg = 4000 g
Answer:
q=15
Step-by-step explanation:
1/5q=9-2/5q
Multiply both sides by 5
q=9*5-2q
3q=45
q=15