Answer:
$12
Step-by-step explanation:
If we stuck with the price of $8, then we end with an income of $2400
Increasing it by $1 will decrease attendance by 20
8 x 300 = 2400
9 x 280 = 2520
10 x 260 = 2600
11 x 240 = 2640
12 x 220 = 2640
13 x 200 = 2600
We're starting to go down, so let's stop there
The ticket price of $11 or $12 appears to give the most income
I would stick with $12 since your still getting more money from one ticket
System of Linear Equations entered :
[1] y - 2x/3 = -1
[2] y + x = 4
// To remove fractions, multiply equations by their respective LCD
Multiply equation [1] by 3
// Equations now take the shape:
[1] 3y - 2x = -3
[2] y + x = 4
Graphic Representation of the Equations :
-2x + 3y = -3 x + y = 4
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -y + 4
// Plug this in for variable x in equation [1]
[1] 3y - 2•(-y +4) = -3
[1] 5y = 5
// Solve equation [1] for the variable y
[1] 5y = 5
[1] y = 1
// By now we know this much :
y = 1
x = -y+4
// Use the y value to solve for x
x = -(1)+4 = 3
I hope this help you
Answer:
jan is 8
Step-by-step explanation:
Answer:
Step-by-step explanation:
v=Q-P
v=(5,1,0)
u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)
u=(5/5.09,1/5.09,0)
v=Q-P
v=(1,1,0)
u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)
u=(1/
,1/,0)
X=10 is the answer to this
