<span><u>Answer </u>
132 〖in〗^2
<u>Explanation </u>
Although the diagram was not given, I was able to get it in the internet.
The area of a trapezium is found by the use of the following formula:
Area =1/2 h(a+b)
Where h is perpendicular distance between the two parallel lines, while a and b is are the lengths of the parallel lines.
In this question;
h=12 in
a=8 in
b=3+8+3=14 in
Area =1/2×12(8+14)
=6×22
132 〖in〗^2
</span>
132 〖in〗^2
<u>Explanation </u>
Although the diagram was not given, I was able to get it in the internet.
The area of a trapezium is found by the use of the following formula:
Area =1/2 h(a+b)
Where h is perpendicular distance between the two parallel lines, while a and b is are the lengths of the parallel lines.
In this question;
h=12 in
a=8 in
b=3+8+3=14 in
Area =1/2×12(8+14)
=6×22
132 〖in〗^2
</span>
