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zhannawk [14.2K]
3 years ago
5

The table of values shows the output values of three different equations for the same

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

  1. x+3
  2. 3x^2
  3. 3^x

Step-by-step explanation:

<u>Relationship 1</u>

The y-values have a common difference of 1, so the relationship is linear with as slope of 1. The only matching choice is (x+3), which matches the values of y1.

__

<u>Relationship 2</u>

The y-values have differences that increase with a common difference. They are (3-0) = 3, (12-3) = 9, (27-12) = 15, (48 -27) = 21. The second differences are (9-3) = 6, (15-9) = 6, and so on with all second differences being 6. This tells you that a second-degree polynomial can model this sequence. The only matching choice is (3x^2), which matches the values of y2.

__

<u>Relationship 3</u>

The y-values have increasing differences that also have increasing differences. The values have a common ratio of 3, indicating an exponential function will model this sequence. The only matching choice is (3^x), which matches the values of y3.

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A store offers 3 for the price of 2. What is the implied discount?
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What is the value of x? 45° 2 (2x - 5) &gt; n​
Vladimir [108]

Answer:

70 degrees

Step-by-step explanation:

Find the diagram attached

The sum of the angles is supplementary that is

45 + 2x- 5 = 180

2x + 40 = 180

2x = 180 - 40

2x = 140

x = 140/2

x = 70

Hence the value of x is 70 degrees

4 0
3 years ago
The first and second terms of a linear sequence (A.p) are 3 and 8 respectively. Please determine the least Number of terms of Ap
Alla [95]

Answer:

To rewrite your question, you are looking for the smallest    that fulfills the inequality:

∑=1>250

First, we must find the sequence    in explicit form. We can think of it as a line we are trying to get the slope-intercept form of. We have the points (1, 3) and (2, 8). Therefore, the slope is  8−32−1=51=5 . Now we just need the y-intercept. We can find it through substitution:

=5+

In order to solve for   , we can plug in one of the points that we were already given. I will choose the point (1, 3). Note that this point just means that when  =1 ,  =3 .

3=5(1)+

3=5+

=−2

Now for the original question.

∑=1(5−2)>250

((5(1)−2)+(5()−2)2)>250

(5+12)>250

522+12>250

2+15>100

2+15+1100>100+1100

(+110)2>100+1100

(+110)2>10001100

+110>±10001100‾‾‾‾‾‾‾√

+110>±11010001‾‾‾‾‾‾√

>−110±11010001‾‾‾‾‾‾√

Since we are looking for the smallest value, we will subtract for the plus or minus sign.

>−110−11010001‾‾‾‾‾‾√≈−10

Since that is negative, we will have to add instead.

>−110+11010001‾‾‾‾‾‾√≈9.9

Therefore, the smallest integer    that makes sense and satisfies the inequality is 10.

So, the first 10 numbers must be added.

Honestly, it would have been quicker just to brute-force this.

Step-by-step explanation:

Have a good day

8 0
2 years ago
Helppppppppppppppppppppppppppppppppppppp
garik1379 [7]

(15a^4 - 30a^5 )/5a^2

= 5a^2(3a^2 - 6a^3) / 5a^2

= 3a^2 - 6a^3

or

= - 6a^3  +  3a^2

4 0
3 years ago
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