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Eva8 [605]
2 years ago
11

Medicine On a college campus of 5000 students, the spread of a flu virus through the student body is modeled by

Mathematics
1 answer:
vlabodo [156]2 years ago
3 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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AB is included between--------
nirvana33 [79]

Answer:

B) ∠A and ∠B

Step-by-step explanation:

AB is the line segment formed with endpoints at A and B.  This means it lies between the angle with vertex at A, ∠A, and the angle with vertex at B, ∠B.

5 0
3 years ago
Read 2 more answers
Which formulas maybe used to find the area of a non right triangle?
Anestetic [448]
Traditional 1/2 * base * height
Heron’s formula (it’s quite lengthy so search it up)
Hope this helped you :)
4 0
3 years ago
What is the greatest value shown on the box-and-whisker plot?
Rainbow [258]
The greatest value shown on the dot and whisker plot is c. 50
4 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
Which sequence of transformations produces R'S'T' from RST? On a coordinate plane, triangle R S T has points (0, 0), (negative 2
arsen [322]

Answer:

Step-by-step explanation:

Given is a triangle RST and another triangle R'S'T' tranformed from RST

Vertices of RST are (0, 0), (negative 2, 3), (negative 3, 1).

Vertices of R'S'T' are  (2, 0), (0, negative 3), (negative 1, negative 1).

Comparing the corresponding vertices we find that x coordinate increased by 2 while y coordinate got the different sign.

This indicates that there is both reflection and transformation horizontally to the right by 2 units

So first shifted right by 2 units so that vertices became

(2,0) (0,3) (-1,1)

Now reflected on the line y=0 i.e. x axis

New vertices are

(2,0) (0,-3) (-1,-1)

8 0
3 years ago
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