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kotykmax [81]
4 years ago
7

Could someone check to see if my answers are correct or not? thanks!

Mathematics
1 answer:
Elza [17]4 years ago
6 0
Hmm... They look OK to me...
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How many seconds are there in 35 minutes?
Sergeu [11.5K]
2,100 seconds are in 35 minutes
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3 years ago
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5) A data set with whole numbers has a low value 20 and high value of 82. Find the class width and class limits for a frequency
Gre4nikov [31]

Answer:

Class width = 9

Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.

Step-by-step explanation:

We are given;

Highest value = 82

Lowest value = 20

Frequency = 7

Formula for class width is;

Class width = (Highest Value - Lowest Value)/number of classes

Class width = (82 - 20)/7

Class width = 8.8 ≈ 9

Now,since class width is 9, limits between 20 and 82 would be done at intervals of 9.

Thus;

Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.

6 0
3 years ago
Please help :)<br> NO LINKS<br> NO silly answers just for fun<br> Please answer Thanks!
Mashcka [7]

Answer:

The second one

Step-by-step explanation:

The equation for volume is l*w*h

l=length

w=width

h=hight

All you have to do is find the answer multiplying all of the numbers together.

Hope this helps!

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3 years ago
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You earn $50,000 dollars per year and the federal tax rate is 10%. Your gross income is
klemol [59]
A because if you multiply 50,000 by .10 (10%) you'll get 5,000
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I just need some help solving this question, i’m not sure what to do
KonstantinChe [14]

From the double-angle identity,

cos2x=2*sinx*cosx

we can rewritte our given equation as:

4sinxcosx-2cosx=0

By factoring 2cosx on the left hand side, we have

2cosx(2sinx-1)=0

This equation has 2 solutions when

\begin{gathered} cosx=0\text{ ...\lparen A\rparen} \\ and \\ 2sinx-1=0\text{ ...\lparen B\rparen} \end{gathered}

From equation (A), we obtain

x=\frac{\pi}{2}\text{ or }\frac{3\pi}{2}

and from equation (B), we have

\begin{gathered} sinx=\frac{1}{2} \\ which\text{ gives} \\ x=\frac{\pi}{6}\text{ or }\frac{5\pi}{6} \end{gathered}

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

\begin{gathered} 2ccos(2\times0)-2cos0=0 \\ which\text{ gives} \\ 2\times1-2\times1=0 \\ so\text{ 0=0} \end{gathered}

then, x=0 is another solution. In summary, we have obtained the following solutions:

\begin{gathered} x=0 \\ x=\frac{\pi}{2}\text{or}\frac{3\pi}{2}\text{ and } \\ x=\frac{\pi}{6}\text{or}\frac{5\pi}{6} \end{gathered}

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:

Therefore, the solution set is: {0}

7 0
1 year ago
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