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sladkih [1.3K]
4 years ago
10

I am confused on this is it 1/8

Mathematics
1 answer:
Oxana [17]4 years ago
6 0
Yes it is 1/8.You don’t multiply the top part of the fraction,just the bottom.
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Simplify the expression ((81y^-8)/(16x^20))^-1/4
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\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
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\\\\
-------------------------------

\bf \left( \cfrac{81y^{-8}}{16x^{20}} \right)^{-\frac{1}{4}}\implies \left( \cfrac{16x^{20}}{81y^{-8}} \right)^{\frac{1}{4}}\implies \left( \cfrac{2^4x^{20}}{3^4y^{-8}} \right)^{\frac{1}{4}}
\\\\\\
\textit{and now we'll distribute the exponent}\qquad \left( \cfrac{2^{4\cdot \frac{1}{4}}x^{20\cdot \frac{1}{4}}}{3^{4\cdot \frac{1}{4}}y^{-8\cdot \frac{1}{4}}} \right)
\\\\\\
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