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Nezavi [6.7K]
2 years ago
8

Will give brainliest!!

Mathematics
1 answer:
Inessa05 [86]2 years ago
4 0
It’s actually B Bc the little 1 by the 10 is meaning that you are gonna multiply 10x10 one time. Then multiply by 7. 10x10=100 100x7=700 so there for your answer is B
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Solve for p: m= 8 -2(p-m)
makkiz [27]
Solve for p by simplifying both sides of the equation, then isolation the variable
p = 1 + m/2

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4 0
3 years ago
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The area of the square, the
const2013 [10]

Answer:

B.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

As given in the question, we know that:

The ratio of the area of the circle to the area  of the square is π/4

  • The formula to find the volume of the cone is:

V = 1/3*the height*the base area

<=> V1 = 1/3*h*πr^{2}

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V2 = 1/3*the height*the base area

<=> V =  1/3*h*4r^{2}

=> the ratio of volume of the cone to the pyramid is:

= \frac{V1}{V2}

= (1/3*h*πr^{2} ) / ( 1/3*h*4r^{2} )

= π/4

S we can conclude that the volume of the cone equals π/4  the volume of the  pyramid

Hope it will find you well.

7 0
2 years ago
How many significant figures are in 0.0624000?
Dafna11 [192]

Answer:

Use notes and youll get an answer

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4 0
2 years ago
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Darya [45]

Answer:

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6 0
2 years ago
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Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

  • 8 ≠ 16
<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

  • 169 = 169
<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

  • 34 ≠ 36
<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

\sf \: 25 + 16 = 49

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<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

3 0
3 years ago
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