12 divide by 1.8 then round down
Answer:
15 ounces per box
Step-by-step explanation:
The rate StartFraction 165 ounces Over 11 boxes EndFraction describes the relationship between the number of boxes and the weight of the crackers in the boxes. What is the weight, in ounces, of one box?
Total weight of crackers in the boxes = 165 ounces
Total number of boxes = 11 boxes
What is the weight, in ounces, of one box?
Weight per box of crackers =
Total weight of crackers in the boxes / Total number of boxes
= 165 ounces / 11 boxes
= 15 ounces per box
The weight, in ounces, of one box is 15 ounces
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer: x = -7
Step-by-step explanation: use the slope formula and slope intercept form y = mx + b to find the equation
Answer:
1
Step-by-step explanation:
15 is a prime number
