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Yuki888 [10]
3 years ago
7

I need help with 1/2x+13=9 im in the 8th grade btw

Mathematics
2 answers:
Inga [223]3 years ago
4 0

Answer:

1/-8

To find:

x

Step-by-step explanation:

1/2x+13=9

take 13 to the LHS. when you take 13 to the LHS it becomes negative

1/2x=9-13

1/2x=-4

by cross multiplying,

2x × -4=1

-8x=1

x=1/-8

hope it helps you!!

frozen [14]3 years ago
3 0

Answer:

-8

Step-by-step explanation:

You are wanting to solve for x

First you want to subtract 13 on both sides-

1/2x = -4

Now you want to divide on both sides-

x = -8

You might be interested in
How do you find direct variation. I’m having trouble understanding some of these examples.
Rufina [12.5K]
Direct variation is a relation that has the form

y = kx

where k is the constant of proportionality.

If you are told that a relation is a direct proportion, and you are given one data point, you can find k. The you can write the equation of the direct relation.

Here is an example.
The price of gasoline follows a direct variation.
John bought 5 gallons of gas and paid $15.
a) Write an equation for the relation.
b) Using the relation you found, how much do 13.8 gallons cost?

Solution:
Since the relation is a direct variation, it follows the general equation of a direct variation:

y = kx

We are given one data point, 5 gallons cost $15.
We plug in  5 for x and 15 for y and we find k.

y = kx
15 = k * 5
k = 3

Now that we know that k = 3, we rewrite the relation using our value of k.

y = 3x

This is the answer to part a).

Part b)

We use our relation, y = 3x, and we plug in 13.8 into x and find y.

y = 3x

y = 3 * 13.8

y = 41.4

The price of 15 gallons of gas is $41.40.
5 0
3 years ago
What's the answer please I need one<br> 200+ 270-56=
Montano1993 [528]

Answer:

414

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Match the key aspect of a function's graph with its meaning.
Margarita [4]

Answer:

Part 1) Intervals of the domain where the  graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero  (y-intercept)

Part 3) location on graph where output is zero  (x-intercept)

Part 4) Intervals of the domain where the  graph is below the x-axis (f(x) < 0)

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) we have

Intervals of the domain where the  graph is above the x-axis

we know that

If the graph is above the x-axis, then the value of f(x) is positive

therefore

f(x) > 0

Part 2) we have

location on graph where input is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The y-intercept is the value of f(x) (output value) when the value of x (input value) is zero

therefore

y-intercept

Part 3) we have

location on graph where output is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the  graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

5 0
3 years ago
2. What are the first two
alexdok [17]

Answer:

6 and 12 is the answers

Step-by-step explanation:

hope this help enjoy your day:)

7 0
3 years ago
Read 2 more answers
HELPPP WILL MARK YOU BRAINLIEST
Tems11 [23]

Answer:

BC = 30

Step-by-step explanation:

AC = 48, AC = AB + BC, AB = 2x + 2 , BC = 3x + 6 => AC = 2x + 2 + 3x + 6  =>

=> AC = 5x + 8 , AC = 48 => 5x = 40 => x = 8 , BC = 3x + 6 => BC = 24 + 6 = 30

3 0
3 years ago
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