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densk [106]
4 years ago
8

Calculate the approximate enthalpy change, ΔHrxn, for the combustion of methane:

Chemistry
2 answers:
VashaNatasha [74]4 years ago
6 0
<span>We subtract the enthalpies of the products by the enthalpies of the reactants, taking into account their stoichiometric coefficients:
</span>2ΔH(H2O) + ΔH(CO2) - ΔH(CH4) - ΔH(2O2)= 2(928) + 1598 - 1656 - 2(498)= 802 kJ / 1 mol methane






Alekssandra [29.7K]4 years ago
5 0
<span>The heat of combustion is obtained by getting the difference between the summation of enthalpies of the products and the enthalpies of the reactants. Hence the equation is enthalpy change= 1598 kJ+2*928 kJ-1656 kJ-498 kJ. The answer is 1300 kJ.</span>
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