Iodine is decolorized.
The first reaction stated in the question occurs as follows;
2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)
The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.
Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.
The equation of the titration reaction is;
2Na2S2O3 + I2→ Na2S4O6 + 2NaI
When this reaction takes place, iodine is decolorized due to its reduction to I^-.
Binary Stars I think
hope this is right and helps
Answer: thermal conductivity
Explanation:
Answer: The value of equilibrium constant for new reaction is
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 
We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:
The equilibrium constant for this reaction will be the cube of the initial reaction.
If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
Hence, the value of equilibrium constant for new reaction is
Given:
Number of items = 25
Price per item = $18
<u>To determine:</u>
The total revenue
<u>Explanation:</u>
Total revenue = quantity * price per item
= 25 items * 18 dollar/ 1 item = $450
Ans: A) The total revenue is $450