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Fittoniya [83]
3 years ago
10

When a solution is diluted, what is the relationship of the number of moles of solute in the more concentrated initial volume of

solution to the number of moles of solute in the less concentrated final volume of solution? A. The ratio of the numbers is directly proportional to the two volumes. B. The ratio of the numbers is inversely proportional to the two volumes. C. The number of moles of solute in the more concentrated initial volume is always greater. D. The number of moles of solute in the less concentrated final volume is always greater. E. The number of moles of solute in both solutions is the same.
Chemistry
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

E. The number of moles of solute in both solutions is the same.

Explanation:

The dilution of a solution consist in increase the volume of solution decreasing, thus, the concentration of the solution. The moles of solute doesn't change in a dilution process.

Thus, when a solution is diluted, the relationship of the number of moles of solute in the more concentrated initial volume of solution to the number of moles of solute in the less concentrated final volume of solution is that:

E. The number of moles of solute in both solutions is the same. TRUE.

I hope it helps!

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A plasma-screen TV contains thousands of tiny cells filled with a mixture of Xe, Ne, and He gases that emits light of specific w
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Answer:

(a) 1.77*10^15 Xe atoms

(b) 2.10*10^16 Ne atoms

(c) 2.10*10^16 He atoms

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Total V = 0.900 mm * 0.300mm * 10.0mm

Total V = 2.7mm cubed

Converting cubed to litres:

2.7mm cubed = 2.7 * 10^-6 Liters

Converting pressure from torr to atm,

(500 torr) * (1 atm ÷ 760 torr) = 0.6578947368 atm

Room temperature is assumed to be 21 degrees celcius, or 294.15 Kelvin

Applying Ideal Gas Equation:

PV = nRT

Therefore, n = PV ÷ RT,

n = [(2.7*10^-6 Liters)(.6578947368 atm)] ÷ [(0.08206)(294.15)]

n = 7.359017079 * 10^-8

Therefore, the total moles present in plasma is 7.359017079 * 10^-8.

(a) To find Xe atoms,

Multiply the total moles present by 4 percent. Therefore,

(7.359017079 * 10^-8)(.04) = 2.943606832*10^-9,

this value gives you Xe moles.

Then multiply by Avogadro's constant:

[(2.943606832*10^-9)(6.022*10^23)] = 1.77*10^15 Xe atoms

(b) and (c) are the same.

Using the total moles number we found in the beginning and minus the number of moles for Xe.

We have:

7.359017079 * 10^-8 - 2.943606832*10^-9 = 7.064656396*10^-8

And Since Ne and He are in a 1:1 ratio, divide this number by two.

We have:

7.064656396*10^-8 ÷ 2 = 3.532328198*10-8 moles

By multiplying this number by Avogadro's number we get atoms:

[(3.532328198*10-8 moles)(6.022*10^23)] = 2.10*10^16

Therefore, the answer for both (b) and (c) is 2.10*10^16.

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