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liubo4ka [24]
3 years ago
10

Suppose y varies directly with x. Write an equation relating x and y.

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0

9514 1404 393

Answer:

  a.  y = -5x

Step-by-step explanation:

The different signs of x and y tell you the constant of proportionality will be negative (eliminating choices <em>b</em> and <em>d</em>).

A quick trial of the given values shows that choice <em>c</em> is incorrect, and that choice <em>a</em> is correct.

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Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


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Given:
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Ipatiy [6.2K]

Answer:

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Step-by-step explanation:

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