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Hunter-Best [27]
3 years ago
15

37= -3 + 5 (x+6) solve for x

Mathematics
2 answers:
Tomtit [17]3 years ago
7 0

Answer:

x = -6

Step-by-step explanation:

1. Pull out like factors: 24+4x=4•(x + 6)

2. Solve: 4=0 (This equation has no solution. A a non-zero constant never equals zero.)

3. Solve: x+6=0 (Subtract 6 from both sides of the equation.)

That's how you will get x = -6

Yanka [14]3 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

37= -3 + 5 (x+6)

Distribute 5(x+6)

37= -3 + 5x + 30

Combine like terms (30-3)

37= 5x + 27

Subtract 27 to both sides (37-27)

10 = 5x

Divide 5 to both sides (10/5)

x = 2

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Please quick problem :)
katen-ka-za [31]
Well find the unit rate first 8 pm to 12 o'clock is 4 hours so -16.8/4=-4.2 degrees per hour since 8. So 1 hour later it would be 0-4.2=-4.2 degrees.
7 0
3 years ago
Can someone help me please?
Naily [24]
Remark
What you can do is solve this system of equations
Let the 2 point questions = x
Let the -1 point questions = y
Let the 0 point questions = n

2x - y = 24
x + y + n = 20  So start by letting x = 14 (just a random number) Solve the first equation.

2x - y = 24
2*14 - y = 24
28 - y = 24  Subtract 28 from both sides.
- y = 24 - 28
- y = - 4
y = 4

Now use the second equation to solve for n
14 + 4 + n = 20
18 + n = 20
n = 20 - 18
n = 2

Answer 1
<em>x = 14</em>
<em>y =  4 </em>
<em>n = 2   Total 20.</em>

This time lets try x = 15 and solve for y
2*15 - y = 24
30 - y = 24
- y = - 6
y = 6 

15 + 6 + n = 20 This obviously will not work. 15 right is too many to be this circumstance. n would have to be -1 and that isn't possible.

Try x = 13
2x - y = 24
2*13 - y = 24
26 - y = 24
-y = 24 - 26
-y = -2
y = 2

Now use the second equation.
x + y + n = 20
13 + 2 + n = 20
15 +n = 20
n= 5

So Answer 2 is
<em>x = 13</em>
<em>y = 2</em>
<em>n = 5  </em>
8 0
3 years ago
Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas
Vadim26 [7]

Answer:

Los radios de los círculos son r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592, respectivamente.

Las áreas de los círculos son A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077, respectivamente.

Step-by-step explanation:

La circunferencia (s) se calcula mediante la siguiente fórmula:

s = 2\pi\cdot r (1)

Donde r es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica (A) mediante la siguiente fórmula:

A = \pi\cdot r^{2} (2)

Si conocemos que las circunferencias son s_{1} = 62.8, s_{2} = 12.65 y s_{3} = 47.7, respectivamente:

1) Radios de los círculos

r_{1} = \frac{s_{1}}{2\pi}, r_{2} = \frac{s_{2}}{2\pi}, r_{3} = \frac{s_{3}}{2\pi}

r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592

2) Áreas de los círculos

A_{1} = \pi\cdot r_{1}^{2}, A_{2} = \pi\cdot r_{2}^{2}, A_{3} = \pi\cdot r_{3}^{2}

A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077

6 0
3 years ago
Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th
Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312

Probability of having an emergency locator and not being discovered:

20% of 28%. So

P(A cap B) = 0.2*0.28 = 0.056

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

P(A) = 1 - 0.5312 = 0.4688

Probability of not having an emergency locator and being discovered:

34% of 72%. So

P(A \cap B) = 0.34*0.72 = 0.2448

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

P(A \cap B) = 0.66*0.72 = 0.4752

Probability of being discovered, given that it has the emergency recorder:

p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946

This question asks for P(X = 7) when n = 10. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064

0.064 = 6.4% probability that 7 of them are discovered.

8 0
3 years ago
BRAINLIEST TO CORRECT QUICK
notsponge [240]

Step-by-step explanation:

hope it helps you......

7 0
3 years ago
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