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2 years ago

In long division what is 601 divided by 3

Mathematics

1 answer:

horrorfan [7]2 years ago

4 0

Who knows cause I don't

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Plz help me <br> I don’t know how to do<br> Number 1 and 2

Rainbow [258]

1. This shape is called a parallelogram and it’s area formula is A=W*H, so you would plug in 12 1/3 for H and 17 1/5 for W. The answer would be 215yd.

2. This is a triangle and it’s area formula is A=1/2bh. Plug in 14 as H and 17 for b. The answer would be 119ft.

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3 years ago

Which of the follow tables do not show a linear function

valina [46]

C , i dont know if it’s right but it’s the only table with the same number on the bottom . and same number in general

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2 years ago

Read 2 more answers

A fence must be built to enclose a rectangular area of 45 comma 000 ftsquared. Fencing material costs $ 3 per foot for the two s

Tatiana [17]

Answer:

150 feet by 300 feet.

Step-by-step explanation:

The fence is to enclose a rectangular area of 45,000 ft squared.

If the dimensions of the rectangle are x and y

Area of a rectangle = xy

xy=45000
$x=\frac{45000}{y}$

Perimeter of the Rectangle =2x+2y

Fencing material costs $ 3 per foot for the two sides facing north and south and $6 per foot for the other two sides.

Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)

Substitute $x=\frac{45000}{y}$ into the Cost to get C(y)

C=12x+6y

$C(y)=12(\frac{45000}{y})+6y\\C(y)=\frac{540000+6y^2}{y}$

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.

$C^{'}(y)=\dfrac{6y^2-540000}{y^2}$

$\dfrac{6y^2-540000}{y^2}=0\\6y^2-540000=0\\6y^2=540000\\y^2=\frac{540000}{6} =90000\\y=\sqrt{90000}=300$

Recall,

$x=\frac{45000}{y}=\frac{45000}{300}=150$

Since x=150, y=300

The dimensions that will be least expensive to build is 150 feet by 300 feet.

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2 years ago

The light from a lamp casts a shadow of a man standing 10 feet away from the lamppost. The shadow is 7 feet long. The angle of e

emmasim [6.3K]

The lamppost is 20 feet long.

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2 years ago

Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. Y=4.5 when x = 3

Nookie1986 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=4.5\\
x=3
\end{cases}\implies 4.5=\cfrac{k}{3}\implies 4.5(3)=k
\\\\\\
13.5=k\qquad therefore\qquad \boxed{y=\cfrac{13.5}{x}}$

8 0

2 years ago