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3 years ago

???????????????????????

Mathematics

1 answer:

aleksandrvk [35]3 years ago

6 0

The answer is 10w.

40 divided by 4 is 10. The X and Y cancel out, leaving 4W.

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Please asap I need this for a test

ki77a [65]

Answer:

Step-by-step explanation:

(f O g) this basically means that the input x first goes trough the function g and then f. Like f(g(x)).

So when x went trough g, you got the output g(x) and then this went trough f and you got f(g(x)) = -8 = 'f(x)'.

With this in mind you can retrace your steps by first looking at what input can get -8 as an output, for f this is -4. this means g(x) = -4

Then you look at what input (this is the x you're looking for) gets you the ouput -4. Looking at the second image you'll picture see that it's the input 3.

4 0

2 years ago

RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that

schepotkina [342]

Answer:

Question 11:

$\angle DAC = 53^\circ$

$\angle AED = 90^\circ$

$\angle ADC = 74$

$DB = 16$

$AE = 6.03$

$AC = 12.06$

Question 12:

$\triangle ABD$ , $\triangle BAC$ , $\triangle CDA$ and $\triangle DAB$

Question 13:

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

Question 11

Given

$\angle BAC = 53^\circ$

$DE = 8$

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): $\angle DAC$

Diagonal CA divides $\angle DAB$ into 2 equal angles

i.e

$\angle DAC = \angle BAC$

So:

$\angle DAC = 53^\circ$

Solving (b): $\angle AED$

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

$\angle AED = 90^\circ$

Solving (c): $\angle ADC$

First, we calculate $\angle ADE$ , considering $\triangle ADE$ :

$\angle ADE + \angle AED + \angle DAC = 180$

$\angle ADE + 90 + 53 = 180$

$\angle ADE + 143 = 180$

$\angle ADE = -143 + 180$

$\angle ADE = 37$

To calculate $\angle ADC$ , we have:

$\angle ADC = 2*\angle ADE$

$\angle ADC = 2* 37$

$\angle ADC = 74$

Solving (d): $DB$

From the rhombus

$DB = DE +EB$

Where

$DE =EB$

So:

$DB = 8 + 8$

$DB = 16$

Solving (e): $AE$

To do this we consider $\triangle ADE$

Using the tan formula

$tan(\angle ADE) = \frac{AE}{DE}$

$\angle ADE = 37$ and $DE = 8$

So:

$\tan(37) = \frac{AE}{8}$

$AE = 8 * \tan(37)$

$AE = 6.03$

Solving (f): $AC$

This is calculated as:

$AC = AE + EC$

Where

$AE = EC$

$AC = 6.03 +6.03$

$AC = 12.06$

Question 12: Isosceles Triangle

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

$\triangle ABD$ , $\triangle BAC$ , $\triangle CDA$ and $\triangle DAB$

Question 13:

AC and BD are perpendicular lines, and they are diagonals

4 0

3 years ago

(5x^+2x-11) - (3x^+8x-7)

omeli [17]

2x^-6x-4 that is the answer

8 0

3 years ago

Ivan bought a $1000 bond with a 4.5% coupon that matures in 30 years. What

Flura [38]

Ivan's annual earnings for this bond is $45.00

A bond is a pledge, made by a borrower to pay a loan taken back to the lender with an interest.

Ivan's annual interest earning would be :

= $1,000 x 4.5 %

= $45 per year

Hence, Ivan's annual earnings for this bond is $45.00

Learn more about bonds here : brainly.com/question/1392006

#SPJ1

5 0

2 years ago

Please help, sorry the image is blurry I retook it multiple times.

Sunny_sXe [5.5K]

Answer:

i dont really know for sure, but try P (-8, 6) Q (-5, 2) and R (2, 1) sorry if its wrong

Step-by-step explanation:

4 0

3 years ago