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3 years ago

Tell me what I did wrong This is really physics but nobody answer questions in physics

Mathematics

2 answers:

Serhud [2]3 years ago

7 0

Answer:

60 m/s

Step-by-step explanation:

2x144000 = 288000J/80kg = 3600J/kg

sqrt 3600 = 60m/s

Naddika [18.5K]3 years ago

5 0

Include m/s with your answer

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If c(x) = 4x – 2 and d(x) = x^2 + 5x, what is (c * d) (x)?

anyanavicka [17]

Answer:

(4x - 2)(x^2 + 5x)

4x^3 + 20x^2 - 2x^2 - 10x

4x^3 + 18x^2 - 10x

Step-by-step explanation:

7 0

3 years ago

Y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP

Nesterboy [21]

Answer:

x intercept (10.5,0)

y intercept (0, -21)

Step-by-step explanation:

y=-2x-21

there are two intercept for a line

x intercept, the point of given equation of line which lies on x axis.

For x intercept corodinate of y is o

Thus, value x intercept is form (x,0)

putting these value in y=-2x-21, we find x intercept

0=-2x-21

2x = 21

x = 21/2 = 10.5

Thus, x intercept (10.5,0)

Y intercept, the point of given equation of line which lies on y axis.

For Y intercept coordinate of x is o

Thus, value y intercept is form (0,y)

putting these value in y=-2x-21, we find y intercept

y = -2*0 -21

y = -21

Thus, y intercept (0, -21)

5 0

3 years ago

Use Heron's formula to find the area of the triangle. Round to the nearest square unit.

kakasveta [241]

Answer:

24.25 in²

Step-by-step explanation:

s = (a + b + c)/2 = (8 + 13 + 7)/2 = 14 in

s - a = 6, s - b = 1, s - c = 7

the area = $\sqrt{14\times6\times1\times7}=24.25$

8 0

3 years ago

WHATS YOUR TIKTOKKK OMG I WANT MUTUALS

OleMash [197]

seth2cold let’s be moots

7 0

3 years ago

One morning, the temperature was -5 ferenhight. By noon, the temperature had increased 12 degrees. What was the temperature at n

Papessa [141]

Answer:

$Noon\ Temperature = 7F$

Step-by-step explanation:

Given

Initial Temperature = -5F

Change (by noon) = 12 degrees

Required

Determine the temperature at noon

The temperature by noon is calculated as thus;

$Noon\ Temperature = Initial\ Temperature + Change$

Substitute values for Initial temperature and change

$Noon\ Temperature = -5F + 12$

$Noon\ Temperature = 7F$

Hence, the temperature at noon is 7F

6 0

4 years ago