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3 years ago

Consider −75/3. Which TWO statements are correct?

Mathematics

2 answers:

kirza4 [7]3 years ago

7 0

Answer:

E and B

Step-by-step explanation: I am pretty sure E is correct because you would have to find the dividend and the divisor.

kiruha [24]3 years ago

3 0

B.) the quotient is -25

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Simplify 6 - (-2) - 3(-5)

seraphim [82]

So the first thing we need to do is multiply 3*-5, since order of operations dictates it (PEMDAS)

$6-(-2)-(-15)$

Now, whenever we see a minus negative number, we can think of it as adding a positive number

$6+(+2)+(+15)$

Now we just add them together

$6+2+15 = 23$

23 is the answer

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3 years ago

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yawa3891 [41]

The answer will be 1.

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Figure ABCD is a parallelogram. Which of the following must be true?

jekas [21]

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3 years ago

Look at the triangle show on the right. The Pythagorean Theorem states that the sum of the squares of the legs of a right triang

Vladimir [108]

Answer:

$cos^2\theta + sin^2\theta = 1$

Step-by-step explanation:

Given

$(\frac{b}{r})^2 + (\frac{a}{r})^2$

Required

Use the expression to prove a trigonometry identity

The given expression is not complete until it is written as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2$

Going by the Pythagoras theorem, we can assume the following.

a = Opposite
b = Adjacent
r = Hypothenuse

So, we have:

$Sin\theta = \frac{a}{r}$

$Cos\theta = \frac{b}{r}$

Having said that:

The expression can be further simplified as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$

Substitute values for sin and cos

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$ becomes

$cos^2\theta + sin^2\theta = 1$

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3 years ago

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vovikov84 [41]

Ask me your other questions.i hope it was helpful

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