I might be wrong but don’t you need two equations to do the elimination process?
Answer:
13 and 77 degrees
Step-by-step explanation:
Complementary = 90 degrees
Set an angle to x
x+(x+64)=90
2x+64=90
2x=26
x=13
angle measures: 13, 77 degrees
9514 1404 393
Answer:
(d) 5a²
Step-by-step explanation:
![\displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B125a%5E6%7D%3D%5Csqrt%5B3%5D%7B5%5E3a%5E6%7D%3D%5Csqrt%5B3%5D%7B%285a%5E2%29%5E3%7D%3D%5Cboxed%7B5a%5E2%7D)
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The applicable rules of exponents are ...
(a^b)^c = a^(bc)
∛a = a^(1/3)
Answer:
AE = 70
Step-by-step explanation:
Given that ACE is a triangle and B , D , F are mid-points of AC, CE, AE respectively.
⇒ BF, FD, BD are mid-segments.
Mid-segment is a line segment joining mid points of two sides of a triangle,
And it as two properties :
1) mid-segment is always parallel to the third side
2) mid-segment is half in length of the third side
⇒ Here, BD is the mid-segment and is parallel to third side AE
And also BD is half of AE
⇒ AE = 2×BD = 2×35
⇒ AE = 70.