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3 years ago

Please answer quick and correctly And im giving brainly

Mathematics

1 answer:

prisoha [69]3 years ago

4 0

Answer:

10 groups you need to make 200.

mark as brainlist

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Solve the system of equations

IceJOKER [234]

<h3>Answer:</h3>

c) there are infinitely many solutions

<h3>Explanation:</h3>

Add x to the <em>first equation</em> to put it in standard form:

... x + y = 3

Divide the <em>second equation</em> by the common factor of all terms, 2, to put it in standard form:

... x + y = 3

These two equations describe the same line. Every point on the line is a solution to both equations, so there are infinitely many solutions. (We say these equations are "dependent.")

3 0

3 years ago

What's the answer to (-6a^-2b^4c^0)^3

Korvikt [17]

-6a -2b^4

^if you simplify, that would be your answer.

4 0

3 years ago

Read 2 more answers

Help me! pleaze help me to do this....give me a step by step answer ..please...

nydimaria [60]

The answer to your question is below this

3 0

3 years ago

[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd

Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 $\frac{f(x+h)-f(x)}{h}$

Now, for the purpose of the function, we need this:

Then we will have:

$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0

1 year ago

Need to know the population in 2015

Margarita [4]

$\bf P=1110.9e^{kt}\quad 
\begin{cases}
P=1200 &\textit{in thousands}\\
t=2 &\textit{in 2002}
\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\$

$\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
\textit{year 2015}
\end{cases}\implies P=1110.9e^{0.0386\cdot 14}
\\\\\\
P\approx 1907.0747\implies about\ 1,907,075\textit{ once rounded up}$

3 0

3 years ago