Answer:
A
Step-by-step explanation:
Answer:
To the nearest hundredth, 2.85
To the nearest hundred, zero
Step-by-step explanation:
Answer:
= −
8/5
Step-by-step explanation:
Distribute
3
(
2
+
3
)
=
1
(
+
1
)
6
+
9
=
1
(
+
1
)
Multiply by 1
6
+
9
=
1
(
+
1
)
6
+
9
=
+
1
Subtract
9
9
9
from both sides of the equation
6
+
9
=
+
1
6
+
9
−
9
=
+
1
−
9
There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
_____
C(n,k) = n!/(k!(n-k)!)
