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3 years ago

Olivia has a piece of ribbon 1/2 yard long. If she cuts

Mathematics

1 answer:

taurus [48]3 years ago

8 0

Answer: 1/12 yd

Step-by-step explanation: .5 yds ÷ 6 = .08333333 yds or as a fraction 1/12 yd

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What percent of discount should be given in a doll costing Rs 180

wolverine [178]

Answer:

11.11%

Step-by-step explanation:

So the question is:

$180 * (x)% = $y

Therefore $180 - $y = $160

Now:

180 - 160 = 20

Therefore; $20 is the discount

Now per cent of discount:

20/180 * 100 = 11.111111111111111111111%

therefore: per cent of discount is 11.11% (rounded to two decimal place)

3 0

3 years ago

Read 2 more answers

)) Omar used 28 centimeters of tape to wrap 4 presents. How much tape will Omar need in

pav-90 [236]

Answer:

He would need 42 cm *or 14cm

Step-by-step explanation:

28/4 is 7

that means that he used 7 cm of tape per present

6 x 7 is 42

that means that he would need 42 cm of tape

4 to 28

6 to 42

*If he already has 4 presents done and he needs to 2 more present then he would need 14 cm, 2 x 7 is 14

8 0

3 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago

What is 7/8 - 4/7 as a fraction

motikmotik

Answer:

17/56

7/8 - 4/7 = 17/56

4 0

3 years ago

Read 2 more answers

The average (arithmetic mean) of 5,10,15 and x is 20..What is the x ?

ruslelena [56]

$Ave=\frac{sum}{count}$
$20=\frac{5+10+15+x}{4}$
$80=30+x$
$x=50$

4 0

3 years ago

Read 2 more answers