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leva [86]
3 years ago
7

A baby who was 18 inches at birth is now 24 inches by what percentage did the babys height increase

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

≈33.3%

Step-by-step explanation:

First we find the difference of the heights to see what the growth was

24-18 = 6

Then we find what percent 6 is of 18 to see what percentage growth occured

6/18 ≈33.3%

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Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1

Then factorizing the difference of squares, x^2-1=(x-1)(x+1), we end up with

\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}

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2 years ago
In a 45-45-90 right triangle, what is the ratio of the length of one leg to the
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Step-by-step explanation:

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Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,
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Answer:

D. x-\frac{5}{2}y =  \frac{25}{2}

Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

x - \frac{5}{2}y = \frac{25}{2}

This is shown as follows;

y = \frac{2}{5}x - 5

Multiply both sides by \frac{5}{2}

\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)

Open Bracket

\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5

\frac{5}{2}y = x - \frac{25}{2}

Subtract x from both sides

\frac{5}{2}y - x = x -x - \frac{25}{2}

\frac{5}{2}y - x = - \frac{25}{2}

Multiply both sides by -1

-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1

-\frac{5}{2}y + x =  \frac{25}{2}

Reorder

x-\frac{5}{2}y =  \frac{25}{2}

<em>Hence, the correct option is D</em>

x-\frac{5}{2}y =  \frac{25}{2}

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