Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
I hope this helps you
2/3÷(-5/6)
2/3× -6/5
2×-6/3×5
-12/15
-4/5
Answer:
slope = - 
Step-by-step explanation:
Differentiating implicitly with respect to x
2x + 2y
= 0
2y
= - 2x
= -
= - 
is the measure of the slope of the tangent
rearrange equation to find corresponding y-coordinate of x = - 2
y² = 16 - 4 = 12 = 2
⇒ y = ± 2
using x = - 2, y = - 2
, then
= -
= - 
Answer:
length = 5
width = 9
Step-by-step explanation:
V = lwh
let 'x' = length
let '4+x' = width
9 = height
405 = 9x(4+x)
405 = 36x + 9x²
this is a quadratic equation: 9x² + 36x - 405 = 0
factor out a 9 to get:
9(x² + 4x - 45) = 0
9(x-5)(x+9) = 0
one root is 5 and the other is -9
since distance cannot be negative we use 5 as the length and 9 is the width
A - bi would be the other complex zero.
When you take the sqrt when solving an equation you get a + and - solution.