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2 years ago

What is the median? A(18 B(27 C(33.2 D(34.5

Mathematics

2 answers:

MakcuM [25]2 years ago

7 0

Answer: 34.5

Step-by-step explanation:

First, write out all of the numbers from least to greatest.

which is (18,20,26,34,34,35,38,40,42,45)

Second, choose the number in the middle of the set of numbers you wrote out from least to greatest. (There are TWO numbers in this case, which are 34 and 35)

Lastly, since there are two numbers you add them both together and then divide by 2. (34+35=69 , 69 divided by 2 = 34.5)

harina [27]2 years ago

3 0

Answer:

C.) 33.2

Step-by-step explanation:

To find the mean you add up all the numbers and divide by how many numbers there are.

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Answer:

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Mrrafil [7]

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3 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

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3 years ago

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Umnica [9.8K]

Answer:

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Step-by-step explanation:

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2 years ago