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Rasek [7]
3 years ago
7

On July 1, 1992, York Co. purchased as a held-to-maturity investment $1,000,000 of Park, Inc.'s 8% bonds for $946,000, including

accrued interest of $40,000. The bonds were purchased to yield 10% interest. The bonds mature on January 1, 1999, and pay interest annually on January 1. York uses the effective interest method of amortization. In its December 31, 1992, balance sheet, what amount should York report as investment in bonds?
Business
1 answer:
professor190 [17]3 years ago
5 0

Answer:

Park Bonds          1,000,000

Discount on bonds (79,400)

Interest receivable   80,000

Carrying value      1,000,600

Explanation:

Investment on Park Bonds 1,000,000

interest receivable                   40,000

                      cash                           946,000

              discount on Park bonds     94,000

Carring value at December 31th 1992

946,000 x 10% = 94,600 interest revenue

Cash proceeds  1,000,000 x 0.08 = 80,000 interest receivable

Discount on Bonds                             14,600

94,000 - 14,600 = 79,400

94,600    interest revenue

(40,000)  accrued interest

54,600    gains for the period

Park Bonds          1,000,000

Discount on bonds (79,400)

Interest receivable   80,000

Carrying value      1,000,600

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I (allowed) and IV (not considered soft dollar compensation)

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A man has $245,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $23
astraxan [27]

Answer:

for 8% investment = $110000

for 12% investment = $55000

for 10% investment =  $80000

annual income for each property is

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Explanation:

Given data

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rate = 8%  twice that invested at 12%

to find out

invested in each property and  the annual income from each property

solution

let us consider x amount for 8% investment

and consider y amount for 12% investment

and consider z amount for 10% investment

from question we say,  8% is twice that invested at 12%

x = 2y      ........1

and

x + y + z = 245000      .............2

put 1 in equation 2

2y + y + z = 245000  

z = 245000 - 3y            ...................3

and we can say that

0.08x + 0.12y + 0.10z = 23400              ...........................4

put equation 1 and 3 in 4

0.08(2y) + 0.12y + 0.10( 245000 - 3y ) = 23400

0.16y + 0.12y - 0.3y = -1100

0.02y = 1100

y = $55000

so x = 2(y) = 2(5500) = $110000

and z = 245000 - 3(55000) = $80000

so annual income for each property is

x amount for 8% investment = 0.08 × 110000 = $8800

y amount for 12% investment = 0.12 × 55000 = $6600

z amount for 10% investment = 0.10 × 80000 = $8000

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