Question

H=2+25t-5t^2 Find all values for t for which the ball height is 12 meters

Answer 1

Answer:

$t=\frac{5-\sqrt{17}}{2},\:t=\frac{5+\sqrt{17}}{2}$

$t=0.43845\dots ,\:t=4.56155\dots$

Step-by-step explanation:

$12=2+25t-5t^2$

$2+25t-5t^2=12$

$-5t^2+25t-10=0$

$\frac{-25+\sqrt{25^2-4\left(-5\right)\left(-10\right)}}{2\left(-5\right)}$

$\frac{-25-\sqrt{25^2-4\left(-5\right)\left(-10\right)}}{2\left(-5\right)}$

$t=\frac{5-\sqrt{17}}{2},\:t=\frac{5+\sqrt{17}}{2}$

$t=0.43845\dots ,\:t=4.56155\dots$