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DENIUS [597]
3 years ago
11

Which table values could be generated by the equation 4y+2x=16

Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

x=0, y=4

x=2, y=5

x=4, y=6

x=6, y=7

x=8, y=8

x=10, y=9

Step-by-step explanation:

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Expand the polynomial (x2 − y2)2 + (2xy)2, then simplify it by combining like terms.
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Write the pair of fractions as a pair of fractions with a common denominator.
galben [10]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Use the table to complete Exercises 2 and 3.
sesenic [268]
Hello!

The Correct Answer's would be: 

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3 0
3 years ago
A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
Read 2 more answers
What is the answer to this question
Lera25 [3.4K]
1.20/4 = 0.3

Hope this helps!

Please mark me as brainliest if you can, I really appreciate it!
5 0
3 years ago
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