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2 years ago

Which figure is not a parallelogram?

Mathematics

2 answers:

Rudiy272 years ago

5 0

Hello, Brainly User!

In Euclidean geometry, a parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

to identify a parallelogram you... it need to have...

Opposite sides are parallel by definition.

Opposite sides are congruent.

Opposite angles are congruent.

Consecutive angles are supplementary.

The diagonals bisect each other.

so therefore the second option would not be correct! if not sure what i mean by second choice i included a screenshot of which one is not a parallelogram!

Hope this helps and i was super glad to help hope you have a fantastic day!

kind regards,

-Philaeagles14

lara31 [8.8K]2 years ago

3 0

Answer:

the second one

Step-by-step explanation:

it does not say that both sides are parallel

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Savannah is 9 years older thanDevante. The sum of their ages is 53. How old are Savannah and Devante?

pickupchik [31]

Answer:

Devante is 23 and Savannah is 32.

Step-by-step explanation:

We can set up a system of equations.

s - savannah's age

d - devante's age

s = d + 9

s + d = 53

Now we can substitute (d + 9) for s in the second equation.

(d + 9) + d = 53

2d + 9 = 53

2d = 46

To find Savannah's age, we just add 9 to Devante's age. (plugging in 23 for d)

23 + 9 = 32

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2 years ago

Is this correct? ILL MARK YOU BRAINIEST

Vsevolod [243]

Answer:

yes

Step-by-step explanation:

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3 years ago

Read 2 more answers

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lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

7 0

1 year ago

Rewrite in logarithmic form 19^2 = 361

Aneli [31]

Answer:

$\log_{19}{361}=2$

Step-by-step explanation:

We know that taking logarithms performs the transformation ...

$b^e=x\\\\e\cdot\log{b}=\log{x}\quad\text{take logs}\\\\e=\dfrac{\log{x}}{\log{b}}\quad\text{divide by $\log{b}$}\\\\\log_b{x}=e\quad\text{use the change of base formula}$