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Serga [27]
3 years ago
9

What is 5 5/12 + 4 11/12 =

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

10 4/12 or 10 1/3

Step-by-step explanation:

First I added the fractions. since they have a common denominator you can add them together easily. 11+5=16 then you will have a improper fraction which would be 16/12 so if you turn it to a proper fraction it would be 1 and 4/12 so then you add the 5+4 and get 9 and then add nine and 1 and 4/12 which is 10 4/12. This fraction can be simplyfied so I divided the 4/12 by 3 and got the fraction in its simpiliest form which is 10 and 1/3.

hammer [34]3 years ago
4 0

Answer:

31/3

Step-by-step explanation:

31/3

10.3

10 1/3

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Sandy wants to make a punch recipe with 2 parts pineapple juice to 6 parts ginger ale if you wants to increase the recipe using
Blizzard [7]

Answer:

24

Step-by-step explanation:

If you go from 2 parts pineapple to 8, thats a 4x increase. Therefore 6x4=24 (6 from the Ginger)

4 0
4 years ago
What subsets of numbers does 8 2/3 belong to?
Ne4ueva [31]
By simplifying the number given which is 8 2/3, we get an improper fraction of 26/3. Also, when we try to divide 26 by 3, we get an answer of 8.6667, with 6 as a repeating number after the decimal place. Therefore, this number is an example of real and rational number. Thus the answer is the second choice. 
5 0
4 years ago
Can someone pls help me
Yuri [45]

Answer:

I'm not sure, but I'll try

Step-by-step explanation:

(Side)^2 = (Hypotenuse)^2 - (Side)^2

(Side)^2 = (9)^2 - ( √ 65 )^2

(Side)^2 = (81) - (65)

(Side)^2 = 16

Take root of answer

Side = √16

Side = 4

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6 0
3 years ago
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iogann1982 [59]
The answer is 5/4 in fraction form

1.25 in decimal form
8 0
3 years ago
Read 2 more answers
Identify the surface with the given vector equation. r(s, t) = s sin 4t, s2, s cos 4t
k0ka [10]

Answer:

Circular paraboloid

Step-by-step explanation:

Given ,

r(s,t)=ssin4t,s^2,scos4t

Here, these are the respective x,y,z axes components.

  • <em>Component along x axis r_i : ssin4t</em>
  • <em>Component along y axis r_j : s^2</em>
  • <em>Component along z axis r_k : scos4t</em>

We see that , from the parameterised equation , r_i^2+r_k^2=s^2sin^24t+s^2cos^24t\\r_i^2+r_k^2=s^2\\r_i^2+r_k^2=r_j

This can also be written as :

x^2+z^2=y

This is similar to an equation of a parabola in 1 Dimension.

By fixing the value of z=0,

<u><em>We get y=x^2 which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.</em></u>

By fixing the value of x=0,

<u><em>We get y=z^2 which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane. </em></u>

Thus by fixing the values of x and z alternatively ,  we get a <u>CIRCULAR PARABOLOID. </u>

4 0
3 years ago
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