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grandymaker [24]
3 years ago
13

Theo and Kade worked on a school project together. Theo worked on the project 3 fewer hours than Kade did. Altogether, they work

ed for a
total of 27 hours. How many hours did they each work on the school project?
Mathematics
2 answers:
Elanso [62]3 years ago
7 0

Answer:

Kade: 15 hours

Theo: 12 hours

Step-by-step explanation:

Personally what I did was subtract (-) 3 from 27 and I got 24 (27-3=24). Then I divided 24 by 2 ( divide by 2 because of Kade and Theo) Then I end up with 12. So I end up with 12 and 12 (but I noticed that didn’t end up equaling 27. So to equal 27 in total I just added 3 to kade since he worked 3 hours more than Theo

babunello [35]3 years ago
6 0

Let the hours Kade worked = X

Theo would be X - 3 ( 3 less than Kade).

Now you have:

X  + X -3 = 27

Combine like terms:

2x - 3 = 27

Add 3 to each side:

2x = 30

Divide both sides by 2:

x = 15

Kade worked 15 hours.

Theo worked 12 hours.

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Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

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Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

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How do you solve 5x-2y= 18 and -5x+3y= -22 by solving a system of linear equations by elimination? Please add the steps in which
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Write the 2 equations:

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Solving this, we get:

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3 years ago
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