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harkovskaia [24]
3 years ago
6

Find the first,fourth, and eighth terms of the sequence. A(n)=-5*2^n-1

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer:

A(1)=-5\times2^1-1=-11

A(1)=-5\times2^4-1=-81

A(1)=-5\times2^8-1=-1281

Step-by-step explanation:

Given :     A(n)=-5\times2^n-1


To find :   A(1), A(4), A(18)


Solution:

Put n=1, A(1)=-5\times2^1-1

               A(1)=-10-1=-11


Put n=4, A(1)=-5\times2^4-1

                A(1)=-80-1=-81

Put n=8, A(1)=-5\times2^8-1=

               A(1)=-1280-1=-1281

Drupady [299]3 years ago
3 0

Answer: A(1)=-5

A(4)=-40

A(8)=-640

Step-by-step explanation:

Given sequence : A(n)=-5\times2^{n-1}

To find the first term, we need to put n=1 in the above sequence , we get

A(1)=-5\times2^{1-1}=-5\times2^0=-5

To find the fourth term, we need to put n=4, we get

A(4)=-5\times2^{4-1}=-5\times2^3=-5\times8=-40

To find the eighth term, we need to put n=8, we get

A(8)=-5\times2^{8-1}=-5\times2^7=-5\times128=-640

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