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Arada [10]
3 years ago
15

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per

pound and cashews cost $6.50 per pound, how many pounds of each should he use? Let p = pounds of peanuts and let c = pounds of cashews. Write a system of equations that could be used to solve the problem.
Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0

Answer: The required system of equations is,

p + c = 10

4.00p + 6.50c = 47.5

Step-by-step explanation:

Here p represents pounds of peanuts and c represents pounds of cashews,

Given,

Total pounds = 10,

⇒ p + c = 10,

Also, the total pounds is sold at the rate of $4.75 per pound,

So, the total expenditure = 4.75 × 10 = $ 47.5

Peanuts cost $4.00 per pound and cashews cost $6.50 per pound,

Total expenditure = ( 4.00p + 6.50c ) dollars,

⇒ 4.00p + 6.50c = 47.5

Oksi-84 [34.3K]3 years ago
4 0
C + p = 10 . . . . . . . . . . . . . . . .the grocer wants 10 lbs of mix
6.50c +4.00p = 4.75*10 . . . . . the total cost of the mix is the sum of costs of contributors to the mix
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for events A and B, P(A)= 3/14 and P(B)= 1/5. Also, P(A and B)= 3/65. Are A and B independent events?
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Step-by-step explanation:

Let us study the meaning independent probability  

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∵ P(A) = \frac{3}{14}

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∴ P(A) . P(B) = \frac{3}{14} × \frac{1}{5}

∴ P(A) . P(B) = \frac{3(1)}{14(5)}

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Learn more:

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4 0
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