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3 years ago

17. What are the three angle measures in the triangle shown below?

Mathematics

1 answer:

lianna [129]3 years ago

4 0

Answer:

Option (1)

Step-by-step explanation:

By using triangle sum theorem in the given triangle,

(5x - 7)° + (11x - 4)° + (3x + 1)° = 180°

(5x + 11x + 3x) - (7 + 4 - 1) = 180

19x - 10 = 180

19x = 190

x = 10

Therefore, (3x + 1)° = 30 + 1

= 30°

(11x - 4)° = 110 - 4

= 106°

(5x - 7)° = 43°

Therefore, Option (1) will be the correct option.

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A tree is 4.5 feet tall. It is expected to grow by 1.75

PtichkaEL [24]

Answer:

20.28571428571429

Step-by-step explanation:

6 0

2 years ago

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Kipish [7]

Answer:

1/4y

Step-by-step explanation:

(-x^-1)^0/(4y^-1*y^2)

anything to the power of 0 gives you 1,

1/(4y^-1*y^2)

-1+2=1

1/4y^1=1/4y

8 0

3 years ago

The perimeter of a rectangle is 60 m and its length is twice its width. find the length of the rectangle

GREYUIT [131]

Length = 2W

P= 2L + 2W
60 = 2(2W) + 2W
60= 4W +2W
60 = 6W
60/6W = 6W/6W
w = 10
Length = 2(10)
Length = 20

P= 2L + 2W
60= 2(20) + 2(10)
60= 40 +20
60 = 60

4 0

2 years ago

PLEASE HELP

xeze [42]

Answer:

-4

Step-by-step explanation:

So we are given the expression: | y - x | + y - 1, and we have our values for (x,y): (-3,-6).

So, we can just start plugging things in and simplifying, so:

| -6 + 3 | - 6 - 1 = | -3 | -7

= 3 - 7

= -4

7 0

3 years ago

Solve for x use the completing the square method x^2+6x=5

Mrac [35]

Answer:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

Step-by-step explanation:

$x^{2}$ +6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power: 3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

$x^{2}$ +6x+9-9-5=0

we have:

$(x+3)^{2}$ -9-5=0

$(x+3)^{2}$ = 14

lets apply square root on both sides of the equation:

$\sqrt{(x+3)^{2}}=\sqrt{14}$

we know:

$\sqrt{a^{2}} = abs(a)$

so we have:

abs(x+3)= $\sqrt{14}$

from where two solutions are obtained

$x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}$

finally we have:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

5 0

3 years ago

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