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evablogger [386]
3 years ago
12

A biker travels the 120 mi from New York , NY to Wilmington, DE in 8 hours. A bus, a truck, and a rider on a horse take the same

route as the biker. At what speed does each of them travel if it takes them 2 hours, 2.5 hours, and 18.75 hours respectively to reach Wilmington? Do the speed and the time vary directly or inversely proportional when the same distance is traveled? Explain why.
Mathematics
1 answer:
pickupchik [31]3 years ago
4 0

Answer:

First, remember the relation:

Distance = Speed*Time.

We know that the distance is 120mi.

A) For the biker we know that:

Time  = 8hours.

Speed = Distance/Time = 120mi/8h = 15 mi/h.

B) For the bus we know that:

Time = 2 hours.

Speed = Distance/Time = 120mi/2h = 60 mi/h.

C) For the truck we know that:

Time = 2.5 hours.

Speed = Distance/Time = 120mi/2.5h = 48 mi/h.

D) For the rider on a horse we know that:

Time = 18.75 hours.

Speed = Distance/Time = 120mi/18.75h = 6.4 mi/h.

E) The equation for the speed is:

Speed = Distance/Time.

You can see that time is in the denominator, this means that if for a fixed distance, the time increases, then the denominator increases, which would imply that the speed decreases.

Then the speed is inversely proportional to the time when the distance is fixed.

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(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

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Factorize

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