Given:
Budget = $30
cost of pizza = $9
cost of drinks = $1
number of pizza = p
number of drinks = d
pizza and drinks should only be equal to or less than the budget of $30.
$9p + $1d <u>< </u>$30
unit cost of pizza : 9
unit cost of drinks : 1
total cost of set (p & d) 10
pizza = 9/10 x 30 = 27 total cost of pizza
drinks =1/10 x 30 = 3 total cost of drinks
27 ÷ 9 = 3 number of pizzas to order
3 ÷ 1 = 3 number of drinks to order
To check:
9p + 1d <u>< </u>30
9(3) + 1(3) <u>< </u>30
27 + 3 <u>< </u>30
30 <u>< </u>30
Answer:
5
Step-by-step explanation:
for the first gear
revolutions/teeth
1 / 24
2 / 48
3 / 72
4 / 96
5 / 120
6 / 144
for the second gear
revolutions/teeth
1 / 40
2 / 80
3 / 120
4 / 160
<em>the two marks will meet after 120 teeth, 5 revolutions of the first gear and 3 revolutions of the second.</em>
the way to get that amount of teeth is


the Least Common Multiple equals the product of all factors, but those factors who are repeted for both numbers should be only once.

120 teeth are 5 revolutions for gear1 and 3 por gear2
How are we supposed to help with this what the heck??
I think it’s D, sorry if I’m wrong.