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Tanya [424]
3 years ago
7

Calculate the mass in atomic mass units of 0.25 mol of carbon-12 atoms

Chemistry
2 answers:
liraira [26]3 years ago
8 0
Each C-12 atom weights 12 amu 
1mol = 6.02*10^23 atoms
6.02*10^23 * 0.25 * 12 = 1.806*10^24
Semmy [17]3 years ago
4 0

Answer : The mass of carbon-12 atoms is, 3 amu

Solution : Given,

Moles of carbon-12 atoms = 0.25 moles

The molar mass of carbon-12 atoms = 12 g/mole = 12 amu

(1 amu = 1 gram/mole)

Now we have to calculate the mass of carbon-12 atoms.

\text{Mass of carbon-12}=\text{Moles of carbon-12}\times \text{Molar mass of carbon-12}

Now put all the given values in this formula, we get the mass of carbon-12 atoms.

\text{Mass of carbon-12}=(0.25moles)\times (12amu)=3amu

Therefore, the mass of carbon-12 atoms is, 3 amu

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30.576 g of hydrogen

Explanation:

First we need to covert the pound in grams.

if        1 pound is equal to 453.592 grams

then  0.3820 pounds is equal to X grams

X = (0.3820 ×  453.592) / 1 = 173.272 grams

So we have 173.272 grams of ammonia.

Now we look at the chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molar weight

number of moles of ammonia = 173.272 / 17 = 10.192 moles

Now taking in account the chemical reaction, we formulate the following reasoning:

if         3 moles of hydrogen produce 2 moles of ammonia

then    Y moles of hydrogen produce 10.192 moles of ammonia

Y = (3 × 10.192) / 2 = 15.288 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 15.288 × 2 = 30.576 g

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3 years ago
While doing a lab a student found the density of a piece of pure aluminum to be 2.85 g/cm3 the accepted value for the density of
____ [38]

Answer:

THE PERCENT ERROR IS 5.55 %

Explanation:

To calculate the percent error, we use the formula:

Percent error = Found value - accepted value / accepted value * 100

Found value = 2.85 g/cm3

Accepted value = 2.70 g/cm3

Solving for the percent error, we have:

Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100

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