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Tanya [424]
3 years ago
7

Calculate the mass in atomic mass units of 0.25 mol of carbon-12 atoms

Chemistry
2 answers:
liraira [26]3 years ago
8 0
Each C-12 atom weights 12 amu 
1mol = 6.02*10^23 atoms
6.02*10^23 * 0.25 * 12 = 1.806*10^24
Semmy [17]3 years ago
4 0

Answer : The mass of carbon-12 atoms is, 3 amu

Solution : Given,

Moles of carbon-12 atoms = 0.25 moles

The molar mass of carbon-12 atoms = 12 g/mole = 12 amu

(1 amu = 1 gram/mole)

Now we have to calculate the mass of carbon-12 atoms.

\text{Mass of carbon-12}=\text{Moles of carbon-12}\times \text{Molar mass of carbon-12}

Now put all the given values in this formula, we get the mass of carbon-12 atoms.

\text{Mass of carbon-12}=(0.25moles)\times (12amu)=3amu

Therefore, the mass of carbon-12 atoms is, 3 amu

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Explanation:

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Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
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Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

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The salt solution is hypertonic to the bacterial cells and as such, water molecules will move from the bacterial cells into the salt solution, dehydrating the cells and rendering them harmless.

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5. 16.3 g of NaCl is dissolved in water to make 1.75 L of solution. What is the molarity of this solution? A 0.159 M B 0.278 M C
ira [324]

Answer: The molarity of this solution is 0.159 M.

Explanation:

Given: Mass of solute = 16.3 g

Volume = 1.75 L

Number of moles is defined as the mass of substance divided by its molar mass.

Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

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Molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.278 mol}{1.75}\\= 0.159 M

Thus, we can conclude that the molarity of this solution is 0.159 M.

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