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Tanya [424]
3 years ago
7

Calculate the mass in atomic mass units of 0.25 mol of carbon-12 atoms

Chemistry
2 answers:
liraira [26]3 years ago
8 0
Each C-12 atom weights 12 amu 
1mol = 6.02*10^23 atoms
6.02*10^23 * 0.25 * 12 = 1.806*10^24
Semmy [17]3 years ago
4 0

Answer : The mass of carbon-12 atoms is, 3 amu

Solution : Given,

Moles of carbon-12 atoms = 0.25 moles

The molar mass of carbon-12 atoms = 12 g/mole = 12 amu

(1 amu = 1 gram/mole)

Now we have to calculate the mass of carbon-12 atoms.

\text{Mass of carbon-12}=\text{Moles of carbon-12}\times \text{Molar mass of carbon-12}

Now put all the given values in this formula, we get the mass of carbon-12 atoms.

\text{Mass of carbon-12}=(0.25moles)\times (12amu)=3amu

Therefore, the mass of carbon-12 atoms is, 3 amu

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What type of energy moves from warmer to cooler?
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3 years ago
A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

Q_1=-Q_2

Mass of steel= m_1

Specific heat capacity of steel = c_1=0.452 J/g^oC

Initial temperature of the steel = T_1=2.00^oC

Final temperature of the steel = T_2=T=21.50^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2= 105 g

Specific heat capacity of water=c_2=4.18 J/g^oC

Initial temperature of the water = T_3=22.00^oC

Final temperature of water = T_2=T=21.50^oC

Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))

On substituting all values:

(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}

<h3>25.0 grams is the mass of the steel bar.</h3>
3 0
3 years ago
Read 2 more answers
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