Answer:
41.67% probability that a student has a dog given that they have a cat
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: having a cat.
Event B: having a dog.
12 of 27 students have a cat:
This means that 
5 students who have a cat and a dog.
This means that 
What is the probability that a student has a dog given that they have a cat?

41.67% probability that a student has a dog given that they have a cat
2^12x-10
Explanation: (the picture)
Answer:
10 times greater
In the first number, 3 represents 30,000, but in the second number 3 represents 3,000 so 30,000 is 10 times greater
Y = mx + b
slope(m) = -4
(-2,5)....x = -2 and y = 5
now we sub into the formula and find b, the y int
5 = -4(-2) + b
5 = 8 + b
5 - 8 = b
-3 = b
so ur equation is : y = -4x - 3 <==
C = caribbean, p = pacific, m = mediterranean
c = p + 29
m = 2p - 30
c + m + p = 719
(p + 29) + (2p - 30) + p = 719
4p - 1 = 719
4p = 719 + 1
4p = 720
p = 720/4
p = 180 <=== pacific paradise deluxe staterooms
c = p + 29
c = 180 + 29
c = 209 <=== caribbean paradise deluxe staterooms
m = 2p - 30
m = 2(180) - 30
m = 360 - 30
m = 330 <=== mediterranean paradise deluxe staterooms