32 × 2 = 68
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:

= 3.90625
Answer:
We know angle AOC is a right triangle,
therefor
90 - 73 = x
Angle X is 17.
Answer:
x > 1/9
Step-by-step explanation:
Given that:
3x-1>-6x
Adding 6x + 1 on both sides we get
3x-1 + 6x + 1>-6x + 6x +1
3x + 6x > 1
Adding both variables
9x > 1
Dividing both sides b 9 we get
9x/9 > 1/9
x > 1/9
I hope it will help you!
Answer:

Step-by-step explanation:
Equation of a line:
The equation of a line, in point slope form, is given by:

In which the point is
and m is the slope.
3/15
This means that 
So

Finding the slope:
Suppose we have two points. The slope is given by the change in the output divided by the change in the input.
3/15
5/25
Change in the output: 25 - 15 = 10
Change in the input: 5 - 3 = 2
So

The equation is:

They are even/equal
(please mark brainliest)