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3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

Mathematics

2 answers:

Yuki888 [10]3 years ago

5 0

Answer:

4/3

Step-by-step explanation:

ac is 12, bc is 9. simplify and you get to 4/3

gogolik [260]3 years ago

4 0

Answer:

3/4 i believe

Step-by-step explanation:

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Stephanie surveyed the students in her class to find out their favorite color. her results are in the table. what percent of Ste

wariber [46]

Hi there!

To solve this problem, we need to find the amount of classmates out of the entire class who did not choose blue as their favorite color and then convert it into a percentage.

First, let's find the fraction:

Since there are 25 total people in her class, since

6 + 9 + 10 = 25

25 is the denominator of the fraction;

Since there are 16 people who did not choose blue,

6 + 10 = 16

16 is the numerator of the fraction.

So, our fraction is 16/25.

Now, we need to convert it into a percentage. To do this, we need to make the denominator 100 by multiplying it by a certain number, and then multiplying the numerator by that same number so the fraction stays equal:

16/25
= 16*4/25*4
= 64/100
= 64%

So, the answer is 64% of Stephanie's classmates.

Hope this helps!

3 0

2 years ago

Nerissa has 5 pink bows, 1 blue bow, and 4 purple bows in a box. She will randomly choose 1 bow from the box. What is the probab

SCORPION-xisa [38]

Answer:2/5

Step-by-step explanation: ok so you take everything and you add it up you get a total of 10 then if you were going to grab a purple one there are 4 purple bows you can then simplify 4/10 to 2/5 and there is your aswer.

3 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

Which of the following mapping diagrams does not represent a function?

Tamiku [17]

Answer:

you'll have to add the answer choices because we can't see what the choices are!

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What subsets of numbers does 8 2/3 belong to?

Ne4ueva [31]

By simplifying the number given which is 8 2/3, we get an improper fraction of 26/3. Also, when we try to divide 26 by 3, we get an answer of 8.6667, with 6 as a repeating number after the decimal place. Therefore, this number is an example of real and rational number. Thus the answer is the second choice.

5 0

3 years ago