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kirza4 [7]
3 years ago
5

Displacement is the change in velocity of an object. a. True b. False

Physics
1 answer:
RUDIKE [14]3 years ago
5 0
True
This is due to the taking outage in into the object.
e.g. You can take a cookie from the cookie jar and add another one into it
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A merry-go-round rotates at the rate of
Mila [183]

Explanation:

Angular momentum is conserved.

I₁ ω₁ = I₂ ω₂

(½ Mr² + md²) ω₁ = (½ Mr²) ω₂

(½ (35 kg) (2.3 m)² + (84 kg) (2.3 m)²) (0.28 rev/s) = (½ (35 kg) (2.3 m)²) ω

ω = 1.624 rev/s

ω = 10.2 rad/s

Round as needed.

6 0
3 years ago
Which term describes electrons being ejected from a metal surface that light is shining on?
spin [16.1K]

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6 0
3 years ago
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At which point will the riders experience centripetal acceleration?
Korvikt [17]

the answer would be (X)

8 0
3 years ago
When u step on the brakes what energy transformation takes place describe the transformation
larisa [96]
Before you step on the brakes, the car has kinetic energy, when you step on the brakes, it turns the kinetic energy into heat (thermal energy). When it stops completely, it has potential energy. Hope this helped :)
5 0
3 years ago
Could I get help on this question please . My parents won’t help me /:
vovikov84 [41]

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.

3 0
3 years ago
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