A vector always consits of
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Answer:
(A) The maximum height of the ball is 40.57 m
(B) Time spent by the ball on air is 5.76 s
(C) at 33.23 m the speed will be 12 m/s
Explanation:
Given;
initial velocity of the ball, u = 28.2 m/s
(A) The maximum height
At maximum height, the final velocity, v = 0
v² = u² -2gh
u² = 2gh
(B) Time spent by the ball on air
Time of flight = Time to reach maximum height + time to hit ground.
Time to reach maximum height = time to hit ground.
Time to reach maximum height is given by;
v = u - gt
u = gt
Time of flight, T = 2t
(C) the position of the ball at 12 m/s
As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.
v² = u² - 2gh
12² = 28.2² - 2(9.8)h
12² - 28.2² = - 2(9.8)h
-651.24 = -19.6h
h = 651.24 / 19.6
h = 33.23 m
Thus, at 33.23 m the speed will be 12 m/s
<u>Answer:</u>
1) 17 N
2) -3 N
3) 14.80 N
4) 4.18 N
5) 12.21 N
<u>Explanation:</u>
The resultant (R) of two forces P and Q acting at an angle θ is given by
We have P = 7N and Q =10N
1) The forces are parallel and act in the same direction ( θ = 0° )
2) The forces are parallel and act in opposite directions( θ = 180° )
3) The forces are inclined at an angle of 60° to each other( θ = 60° )
4) The forces are inclined at an angle of 160°( θ = 160° )
5) The forces act at 90° to each other( θ = 90° )