A vector always consits of

Two sound waves are traveling through the same medium. They have the same amplitude, wavelength, and direction of travel. If the

Sloan [31]

Answer:

Constructive interference

Explanation:

Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.

Let the intensity of waves be I which is same for both

The formula for the net intensity is

$I^{2}=I_{1}^{2}+I_{2}^{2}+2I_{1}I_{2}Cos\phi$

where, Ф be the phase difference

So, $I_{R}^{2}=I^{2}+I^{2}+2IICos6\pi$

Here, IR is maximum so the interference is constructive in nature.

7 0

4 years ago

The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find

natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

$F_A=G\frac{M_Am}{R_A^2}$

For planet B,

$F_B=G\frac{M_Bm}{R_B^2}$

We also know that the weight of the object on the two planets is the same, so

$F_A = F_B$

So we can write

$G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}$

We also know that the mass of planet A is only sixty percent that of planet B, so

$M_A = 0.60 M_B$

Substituting,

$G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}$

Now we can elimanate G, MB and m from the equation, and we get

$\frac{0.60}{R_A^2}=\frac{1}{R_B^2}$

So the ratio between the radii of the two planets is

$\frac{R_A}{R_B}=\sqrt{0.60}=0.775$

6 0

3 years ago

What is the relationship between refraction and the speed of light?

tankabanditka [31]

Answer:

$n=\frac{c}{v}$

Explanation:

Refraction: It is a process in which light ray travel from one medium to another medium.

When a light travel form one medium to another medium then the speed of light changes.

When a light travel from rare to denser medium then the light bend towards normal .

When a light travel form denser to rare medium then the light ray bend away from the normal.

Refractive index:It is a ratio of velocity of light in vacuum to the velocity of light in medium .It is a measure of change in speed of light when it passes from vacuum into material.It is represented by "n''.

Mathematical representation:

$n=\frac{c}{v}$

Where n=Refractive index of material

c=Velocity of light in vacuum

v=Velocity of light in medium

8 0

3 years ago

A horizontal compass is placed 21 cm due south from a straight vertical wire carrying a 36 a current downward. in what direction

Anit [1.1K]

The needle of a compass will always lies along the magnetic field lines of the earth.
A magnetic declination at a point on the earth’s surface equal to zero implies that
the horizontal component of the earth’s magnetic field line at that specific point lies along
the line of the north-south magnetic poles.

The presence of a current-carrying wire creates an additional 
magnetic field that combines with the earth’s magnetic field. Since magnetic
fields are vector quantities, therefore the magnetic field of the earth and the magnetic field of the vertical wire must be combined vectorially.

Where:

B1 = magnetic field of the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T

B2 = magnetic field due to the straight vertical wire along the y-axis

We can calculate for B2 using Amperes Law:

B2 = μ₀ i / [ 2 π R ]

B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ] 
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T

The angle can be calculated using tan function:
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T 
tan θ = 1.326

θ = 53°

The compass needle points along the direction of 53° west of north.

8 0

4 years ago

Find the wavelength of light given off by a hydrogen atom when its electron drops from the n = 4 to n = 1 energy level

4vir4ik [10]

Answer: 1.55 x 10 -19J on top

Explanation:

4 0

3 years ago