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zvonat [6]
3 years ago
11

Solve for x: 11x = 6x + 20

Mathematics
2 answers:
notka56 [123]3 years ago
3 0

Answer:

x = 4

Step-by-step explanation:

11x= 6x +20

-6x   -6x

(subtract 6x from both sides)

5x = 20

/5x   /5x

divide 5x from both sides

x=4

Phoenix [80]3 years ago
3 0
Answer is x = 4

11x = 6x +20
-6x -6x

5x = 20
/5 /5

X= 4
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Carlos walked to school on 14 of the 20 school days in February. Which value is equivalent to the fraction of the school days in
BabaBlast [244]

Answer:

70%. let me break it down

Step-by-step explanation:

step 1:

14 divided by 20 is 0.7

step 2:

14/20 x 100 so we can work our way to the percentages and the answer is 70% , your probably asking, how? because 70/100 is gonna give 0.7 (7/10) so it is really similar

6 0
3 years ago
If you can help with as many as you can that would be greatly appreciated.
Solnce55 [7]
9.   0.26666
10. 2.375
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6 0
3 years ago
Given that the line is x/3 + y/2 =1<br> i ) make y the subject<br> ii ) gradient of line
miss Akunina [59]

Answer:

see explanation

Step-by-step explanation:

(i)

\frac{x}{3} + \frac{y}{2} = 1 ( multiply through by 6 to clear the fractions )

2x + 3y = 6 ( subtract 2x from both sides )

3y = - 2x + 6 ( divide through by 3 )

y = - \frac{2}{3} x + 2

(ii)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope ( gradient ) and c the y- intercept )

y = - \frac{2}{3} x + 2 ← is in slope- intercept form ( that is part (i)

with gradient m = - \frac{2}{3}

7 0
2 years ago
What are the roots of x in -10x2 + 12x − 9 = 0?
hoa [83]

Answer:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

Step-by-step explanation:

Use the Quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

You can identify that, in this case:

a=-10\\b=12\\c=-9

Now you need to substitute these values into the formula:

x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}

x=\frac{-12\±\sqrt{-216}}{-20}

Remember that:

i=\sqrt{-1}

Therefore,rewriting and simplifying, you get:

x=\frac{-12\±6i\sqrt{6}}{-20}

x=\frac{-6(2\±i\sqrt{6})}{-2(10)}

x=\frac{3(2\±i\sqrt{6})}{10}

Then, you get the following roots:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

6 0
3 years ago
Read 2 more answers
Find the length of the missing side. Leave your answer in simplest radical form.
Hatshy [7]

Answer:

The SQ Root of 493

Step-by-step explanation:

Becaues this triangle is a right triangle, we can find the missing side usiing the pythagorean theorum.

The pythagorean theorun states A^2 + B^2 = C^2, so 18^2 + 13^2= 439

Then all you have to do is find the sq root of 439, but this question askes you not to.

Hope this helps :)

7 0
3 years ago
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