A system of equations where both X and Y cancel and you are left with just a number is called

Mathematics

1 answer:

dimulka [17.4K]3 years ago

4 0

Elimination method I think not completely sure

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M^1/3 divided by m^1/5

alisha [4.7K]

M^1/3 divided by m^1/5 = m^2/15<span>

m^1/5 divided by m^1/3 = 1/ </span>m^2/15<span>

m^1/3*m^1/5 = m^8/15

(m^1/3)^1/5 = m^1/15

(m^1/3m^1/5)^0 =1</span>

4 0

3 years ago

What is the y intercept of the line 2x + 5y = -10? a.2 b.-2 c.5 d.-5

mafiozo [28]

The y intercept is when x=0
0+5y=-10
y=-2

6 0

3 years ago

Read 2 more answers

An object is launched vertically upward from a 25 foot platform and is modeled by the function s(t)=−16t2+11t+25.

ch4aika [34]

Correct option:

d. 1.64

<h2>Explanation:</h2>

An object is launched vertically upward from a 25 foot platform and is modeled by the following function:

$s(t)=-16t^2+11t+25$

So this is the equation of a parabola because the object is a projectile so it follows the Projectile Motion.

The object fall back to the ground when $s(t)=0$ so:

$-16t^2+11t+25=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ t_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16 \\ \\ b=11 \\ \\ c=25 \\ \\ \\ t_{12}=\frac{-11\pm \sqrt{11^2-4(-16)(25)}}{2(-16)} \\ \\ t_{12}=\frac{-11\pm 41.48}{-32} \\ \\ t_{1}=\frac{-11+ 41.48}{-32}=-0.95s \\ \\ t_{2}=\frac{-11- 41.48}{-32}=1.64s$