Answer:
75%
Step-by-step explanation:
3/4 = 75/100
Answer:
Step-by-step explanation:
Given that the Acme Company manufactures widgets, which have a mean of 60 ounces and a standard deviation of 7 ounces
We know that 95% of the area lie between -2 and 2 std deviations from the mean.
i.e. Probability for lying in the middle of 95%
Z score 
Between 46 and 74 oz.
b) Between 12 and 57
convert into Z score

P(-6.86<z<-0.43)
=0.5-0.1664=0.3336
c) X<30 gives Z<-4.83
i.e. P(X<30) =0.00
The < is just like and equal sign just looks a little different think of it that was for the first couple steps. So you have 13-3y<-5. First do, -5+13=8. Now you have -3y<8. Then your want to do 8 divided by -3 and you get=-2.666666667 and that equals y.
-2.7=y then make that equal sign into the normal sign again. -2.7
Answer:
There were 30 children and 10 adults.
Step-by-step explanation:
Since they sold tickets to adults and childrens, the sum of those tickets must be equal to the total tickets that were sold, so we can mount our first equation as shown below:
adult + children = 40
Each adult ticket costs $9 and each children costs $5 and the total recieved was $240, therefore:
9*adult + 5*children = 240
We can mount the following equation system:
adult + children = 40
9*adult + 5*children = 240
We will multiply the first equation by -5 and sum both equations:
-5*adult -5*children = -200
9*adult + 5*children = 240
4*adult = 40
adult = 40 / 4
adult = 10
adult + children = 40
children = 40 - adult = 40 - 10 = 30
There were 30 children and 10 adults.
There is no relationship between the number of hours cycled and the number of hours worked (Option D).
<h3>What is a scatterplot?</h3>
A scatterplot is a graph that is used to show the association between two variables. The relationship between the variables is shown by the use of line of best fit.
From the scatterplot shown, we can conclude that there is no relationship between the number of hours cycled and the number of hours worked (Option D).
Learn more about scatterplot:brainly.com/question/25280625
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