Nathan has 80 stamps in his collection. He adds 1 stamp to it today. Each day he plans to add twice the number of stamps as the
previous day. If he keeps adding stamps at this rate for n days, which recursive function represents the number of stamps he has on any day in the future?
111 We start with 80 and we add 1 on the first day, 2 on the 2nd, 4 on the 3rd, etc.. Looking at the numbers being added 1 = 202 = 214 = 228 = 2316 = 24...We start with 80 and we add 2n to it where n represents the number of days into the iterationwith n starting at 0 The function that shows how many stamps we have on any given day is <span> D</span><span>S = 80 + ∑ 2<span>n </span>Where D is the number of days we are into the iteration</span><span> n=0</span>NOTE: This starts at day 0 which would be S = 80 + 20 = 80 + 1 = 81 stamps Example: To find how many stamps we have on D = 4 we would haveS = 80+20+21+22+23+24 = 80+1+2+4+ 8+16 = 111 stamps
when you simplify you continue until you get to the simplest form but when you solve you continue until you get an answer. Solving gives you a value for a variable. You mean simplify and get 2x - 10 but when you solve you continue until you get x as 5