The answer is <span>(-1, -6)
</span>
Let's go through all choices:
1. (x, y) = (-10, 17)
x + y = 7
-10 + 17 = 7
17 - 10 = 7
7 = 7
So, these points lie on the line.
2. (x, y) = (<span>13/3, 8/3)
</span>x + y = 7<span>
13/3 + 8/3 = 7
(13 + 8)/3 = 7
21/3 = 7
7 = 7
</span>So, these points lie on the line, too.
3. (x, y) = <span>(-1, -6)
</span>x + y = 7
-1 + (-6) = 7
-1 - 6 = 7
-7 ≠ 7
So, these points DO NOT lie on the line.
In any given right triangle, the Pythagorean Theorem can be used to show that it is a right triangle.
The Pythagorean Theorem is a^2+b^2=c^2. In a right triangle, a and b would be the shorter legs of the triangle, while c would be the hypotenuse.
So for this problem, you would plug in the numbers in the order that they are listed to see if it is a right triangle.
F would be: 2^2+4^2=7^2. In this case, the sides are not equal.
G would be: 6^2+8^2=10^2. In this case, 100=100. So this is a right triangle.
H would be: 4^2+9^2=12^2. The sides are not equal.
J would be: 5^2+10^2=15^2. The sides are not equal.
Your answer would be G, since the sides are equal. Hope this helps! :)
Answer:
2 2/5
Step-by-step explanation:
3/4 divided by 5/16 = 12/5
12 goes into 5 2 times making
2 2/5
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) 
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) 
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
